Cho a;b;c;d khác 0 biết \(\dfrac{2a}{3b}\) = \(\dfrac{3b}{4c}\)= \(\dfrac{4c}{5d}\) = \(\dfrac{5d}{2a}\). Tính C = \(\dfrac{2a}{3b}\) + \(\dfrac{3b}{4c}\) + \(\dfrac{4c}{5d}\) + \(\dfrac{5d}{2a}\)

Các câu hỏi liên quan