\(\Rightarrow\) + Nếu a>b thì \(\dfrac{a.b+a.2017}{b.\left(b+2017\right)}>\dfrac{b.a+b.2017}{b.\left(b+2017\right)}\Leftrightarrow\dfrac{a}{b}>\dfrac{a+2017}{b+2017}\)
+ Nếu a
+ Nếu a=b thì \(\dfrac{a.b+a.2017}{b.\left(b+2017\right)}=\dfrac{b.a+b.2017}{b.\left(b+2017\right)}\Leftrightarrow\dfrac{a}{b}=\dfrac{a+2017}{b+2017}\)