Cho biết \(\dfrac{a}{b} < 1,b \ne 0\) và \(c > 0\). Chứng tỏ rằng \(\dfrac{a}{b} < \dfrac{{a + c}}{{b + c}}\).
A.\(\dfrac{a}{b} < \dfrac{{a + c}}{{b + c}}\)
B.\(\dfrac{a}{b} = \dfrac{{a + c}}{{b + c}}\)
C.\(\dfrac{a}{b} > \dfrac{{a + c}}{{b + c}}\)
D.\(\dfrac{a}{b} + \dfrac{{a + c}}{{b + c}}=\dfrac{2a}{b}\)
A.\(\dfrac{a}{b} < \dfrac{{a + c}}{{b + c}}\)
B.\(\dfrac{a}{b} = \dfrac{{a + c}}{{b + c}}\)
C.\(\dfrac{a}{b} > \dfrac{{a + c}}{{b + c}}\)
D.\(\dfrac{a}{b} + \dfrac{{a + c}}{{b + c}}=\dfrac{2a}{b}\)
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