Đáp án:
\(\begin{array}{l}
b)\\
{m_{{C_6}{H_{12}}{O_6}}} = 90g\\
c)\\
{V_r} = 230ml
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a)\\
{C_6}{H_{12}}{O_6} \to 2{C_2}{H_5}OH + 2C{O_2}\\
b)\\
{n_{C{O_2}}} = \dfrac{{22,4}}{{22,4}} = 1mol\\
{n_{{C_6}{H_{12}}{O_6}}} = \dfrac{{{n_{C{O_2}}}}}{2} = 0,5mol\\
{m_{{C_6}{H_{12}}{O_6}}} = 0,5 \times 180 = 90g\\
c)\\
{n_{{C_2}{H_5}OH}} = {n_{C{O_2}}} = 1mol\\
{m_{{C_2}{H_5}OH}} = 1 \times 46 = 46g\\
{V_{{C_2}{H_5}OH}} = \dfrac{{46}}{{0,8}} = 57,5ml\\
{V_r} = \dfrac{{57,5 \times 100}}{{25}} = 230ml
\end{array}\)