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Nguyenphuqui147@
2 năm trước
Cho đường tròn(O;R) đường kính AB cố định.Trên tia đối của AB lấy điểm AC=R.Kẻ đường thẳng d vuông góc với BC tại C.Gọi D là trung điểm của OA; qua D vẽ dây cung EF bất kì của (O;R) ,( EF không là đường kính của (O;R)).Tia BF cắt d tại N. Chứng minh tứ giác MCAE nội tiếp
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