Đáp án:
13 B
15 B
Giải thích các bước giải:
\(\begin{array}{l}
13)\\
CTTQ\,\,2\,anken:{C_n}{H_{2n}}\\
{C_n}{H_{2n}} + B{r_2} \to {C_n}{H_{2n}}B{r_2}\\
nB{r_2} = \dfrac{{24}}{{160}} = 0,15\,mol\\
n{C_n}{H_{2n}} = nB{r_2} = 0,15\,mol\\
15)\\
nX = \dfrac{{3,36}}{{22,4}} = 0,15\,mol\\
{C_n}{H_{2n}} + B{r_2} \to {C_n}{H_{2n}}B{r_2}\\
m{C_n}{H_{2n}} = m\, = 7,7g\\
M{C_n}{H_{2n}} = \dfrac{{7,7}}{{0,15}} = 51,33g/mol\\
\Rightarrow 14n = 51,33 \Rightarrow n = 3,67\\
\Rightarrow CTPT:{C_3}{H_6};{C_4}{H_8}
\end{array}\)
