Đáp án:
\(b.T = \frac{{ - 809}}{{180}}\)
Giải thích các bước giải:
\(\begin{array}{l}
F\left( x \right) = \frac{1}{2}{x^3} - \frac{7}{4}x + 3{x^2} - \frac{{11}}{5}\\
= \frac{1}{2}{x^3} + 3{x^2} - \frac{7}{4}x - \frac{{11}}{5}\\
G\left( x \right) = 2x - 7{x^2} + \frac{1}{2}{x^3} - \frac{4}{9}\\
= \frac{1}{2}{x^3} - 7{x^2} + 2x - \frac{4}{9}\\
a.F\left( x \right) + H\left( x \right) = G\left( x \right)\\
\to H\left( x \right) = G\left( x \right) - F\left( x \right)\\
= \frac{1}{2}{x^3} - 7{x^2} + 2x - \frac{4}{9} - \frac{1}{2}{x^3} - 3{x^2} + \frac{7}{4}x + \frac{{11}}{5}\\
= - 10{x^2} + \frac{{15}}{4}x + \frac{{79}}{{45}}\\
b.T = - 10 + \frac{{15}}{4} + \frac{{79}}{{45}} = \frac{{ - 10.180 + 15.45 + 79.4}}{{4.45}}\\
= \frac{{ - 809}}{{180}}
\end{array}\)
