Đáp án:
\(\begin{array}{l}
a)\,\,\,\,m = - \frac{3}{2}\,\\
b)\,\,\,m = 1\\
c)\,\,\,\,m = 1\\
d)\,\,\,m = \frac{4}{3}
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
d:\,\,\,y = \left( {2 - 3m} \right)x + 2m\\
Ham\,\,\,so\,\,la\,\,\,ham\,\,\,so\,\,bac\,\,nha \Rightarrow 2 - 3m \ne 0\\
\Leftrightarrow m \ne \frac{2}{3}\\
a)\,\,\,Dths\,\,\,cat\,\,\,Oy\,\,\,\,tai\,\,\,diem\,\,\,co\,\,tung\,\,\,do\,\, = - 3\\
\Rightarrow d\,\,\,di\,\,qua\,\,\,A\left( {0; - 3} \right)\\
\Rightarrow - 3 = \left( {2 - 3m} \right).0 + 2m\\
\Leftrightarrow 2m = - 3 \Leftrightarrow m = - \frac{3}{2}\,\,\,\,\left( {tm} \right).\\
b)\,\,\,Dths\,\,\,cat\,\,\,Ox\,\,\,\,tai\,\,\,diem\,\,\,co\,\,hoanh\,\,\,do\,\, = 2\\
\Rightarrow d\,\,di\,\,qua\,\,\,B\left( {2;\,\,0} \right)\\
\Rightarrow 0 = \left( {2 - 3m} \right).2 + 2m\\
\Leftrightarrow 4 - 6m + 2m = 0\\
\Leftrightarrow 4m = 4\\
\Leftrightarrow m = 1\,\,\,\,\left( {tm} \right).\\
c)\,\,\,Dths\,\,\,di\,\,\,qua\,\,\,goc\,\,toa\,\,do\\
\Rightarrow d\,\,\,di\,\,\,qua\,\,\,O\left( {0;\,\,0} \right)\\
\Rightarrow 2m = 0 \Leftrightarrow c\,\,\,\left( {tm} \right).\\
d)\,\,\,d//d':\,\,y = - 2x\\
\Rightarrow \left\{ \begin{array}{l}
2 - 3m = - 2\\
2m \ne 0
\end{array} \right. \Leftrightarrow \left\{ \begin{array}{l}
3m = 4\\
m \ne 0
\end{array} \right. \Leftrightarrow \left\{ \begin{array}{l}
m = \frac{4}{3}\\
m \ne 0
\end{array} \right. \Leftrightarrow m = \frac{4}{3}\,\,\,\left( {tm} \right).
\end{array}\)
