Cho hàm số \(f\left( x \right) = {\left( {\sqrt x - \frac{1}{{\sqrt x }}} \right)^3}\). Hàm số có đạo hàm \(f'\left( x \right)\) bằng:
A.\(\frac{3}{2}\left( {\sqrt x + \frac{1}{{\sqrt x }} + \frac{1}{{x\sqrt x }} + \frac{1}{{{x^2}\sqrt x }}} \right)\)
B.\(x\sqrt x - 3\sqrt x + \frac{3}{{\sqrt x }} - \frac{1}{{x\sqrt x }}\)
C.\(\frac{3}{2}\left( { - \sqrt x + \frac{1}{{\sqrt x }} + \frac{1}{{x\sqrt x }} - \frac{1}{{{x^2}\sqrt x }}} \right)\)
D.\(\frac{3}{2}\left( {\sqrt x - \frac{1}{{\sqrt x }} - \frac{1}{{x\sqrt x }} + \frac{1}{{{x^2}\sqrt x }}} \right)\)
A.\(\frac{3}{2}\left( {\sqrt x + \frac{1}{{\sqrt x }} + \frac{1}{{x\sqrt x }} + \frac{1}{{{x^2}\sqrt x }}} \right)\)
B.\(x\sqrt x - 3\sqrt x + \frac{3}{{\sqrt x }} - \frac{1}{{x\sqrt x }}\)
C.\(\frac{3}{2}\left( { - \sqrt x + \frac{1}{{\sqrt x }} + \frac{1}{{x\sqrt x }} - \frac{1}{{{x^2}\sqrt x }}} \right)\)
D.\(\frac{3}{2}\left( {\sqrt x - \frac{1}{{\sqrt x }} - \frac{1}{{x\sqrt x }} + \frac{1}{{{x^2}\sqrt x }}} \right)\)
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Hóa Học lớp 12
