Cho hàm số \(f \left( x \right) = \dfrac{{2x + a}}{{x - b}} \, \, \left( {a,b \in R, \, \,b \ne 1} \right) \). Ta có \(f' \left( 1 \right) \) bằng:
A.\(\dfrac{{ - a - 2b}}{{{{\left( {b - 1} \right)}^2}}}\)
B.\(\dfrac{{a + 2b}}{{{{\left( {1 - b} \right)}^2}}}\)
C.\(\dfrac{{ - a + 2b}}{{{{\left( {b - 1} \right)}^2}}}\)
D.\(\dfrac{{a - 2b}}{{{{\left( {b - 1} \right)}^2}}}\)
A.\(\dfrac{{ - a - 2b}}{{{{\left( {b - 1} \right)}^2}}}\)
B.\(\dfrac{{a + 2b}}{{{{\left( {1 - b} \right)}^2}}}\)
C.\(\dfrac{{ - a + 2b}}{{{{\left( {b - 1} \right)}^2}}}\)
D.\(\dfrac{{a - 2b}}{{{{\left( {b - 1} \right)}^2}}}\)
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Hóa Học lớp 12
