Đáp án:
$F\left(\dfrac{\pi}{2}\right) - F(0) =\dfrac14$
Giải thích các bước giải:
$\quad F(x)=\displaystyle\int\sin^3x\cos xdx$
$\to F(x)=\displaystyle\int\sin^3xd(\sin x)$
$\to F(x)=\dfrac14\sin^4x +C$
Khi đó:
$\quad F\left(\dfrac{\pi}{2}\right) - F(0)$
$= \dfrac14\sin^4\dfrac{\pi}{2} - \dfrac14\sin^40$
$=\dfrac14$