Cho hàm số \(y = f\left( x \right) = - \frac{2}{5}x + 3\). Tính: \(f\left( { - 5} \right)\,\,;\,\,f\left( {0,7} \right)\,\,;\,\,f\left( {3\frac{1}{4}} \right)\). Kết quả lần lượt là:
A.\(f\left( { - 5} \right) = 5\); \(f\left( {0,7} \right) = \frac{{38}}{{25}}\); \(f\left( {3\frac{1}{4}} \right) = f\left( {\frac{{13}}{4}} \right) = \frac{{17}}{{10}}\)
B.\(f\left( { - 5} \right) = 5\); \(f\left( {0,7} \right) = \frac{{-68}}{{25}}\); \(f\left( {3\frac{1}{4}} \right) = f\left( {\frac{{13}}{4}} \right) = \frac{{17}}{{10}}\)
C.\(f\left( { - 5} \right) = -5\); \(f\left( {0,7} \right) = \frac{{68}}{{25}}\); \(f\left( {3\frac{1}{4}} \right) = f\left( {\frac{{13}}{4}} \right) = \frac{{17}}{{10}}\)
D.\(f\left( { - 5} \right) = 5\); \(f\left( {0,7} \right) = \frac{{68}}{{25}}\); \(f\left( {3\frac{1}{4}} \right) = f\left( {\frac{{13}}{4}} \right) = \frac{{17}}{{10}}\)
A.\(f\left( { - 5} \right) = 5\); \(f\left( {0,7} \right) = \frac{{38}}{{25}}\); \(f\left( {3\frac{1}{4}} \right) = f\left( {\frac{{13}}{4}} \right) = \frac{{17}}{{10}}\)
B.\(f\left( { - 5} \right) = 5\); \(f\left( {0,7} \right) = \frac{{-68}}{{25}}\); \(f\left( {3\frac{1}{4}} \right) = f\left( {\frac{{13}}{4}} \right) = \frac{{17}}{{10}}\)
C.\(f\left( { - 5} \right) = -5\); \(f\left( {0,7} \right) = \frac{{68}}{{25}}\); \(f\left( {3\frac{1}{4}} \right) = f\left( {\frac{{13}}{4}} \right) = \frac{{17}}{{10}}\)
D.\(f\left( { - 5} \right) = 5\); \(f\left( {0,7} \right) = \frac{{68}}{{25}}\); \(f\left( {3\frac{1}{4}} \right) = f\left( {\frac{{13}}{4}} \right) = \frac{{17}}{{10}}\)
Loga
Hóa Học lớp 12
