Giải thích các bước giải:
a)
Ta có `S_(ADC = 1/2 S_(ABCD`
`S_(DCK = 1/2 S_(BDC`
`=2/3 . 1/2 S_(ABCD`
`= 1/3 S_(ABCD`
`=>` `S_(ADC)/S_(DCK) = 1/2 S_(ABCD) : 1/2 S_(ABCD) = 3/2`
b)
Ta có: `S_(ABCD) = S_(ABD) + S_(BDL)`
`=1/2S_(ABCD) + 2/3S_(BDC)`
`=1/2S_(ABCD) + 1/3S_(ABCD`
`=5/6S_(ABCD)`
`=>` `S_(ABC)/S_(ADLB) = 1/2S_(ABCD) . 5/6S_(ABCD) = 3/6`
c)
`S_(ABKD)/S_(ABLD)= (2/3S_(ABCD))/(5/6S_(ABCD)) = 4/5`
≈Học tốt≈