Đáp án đúng: D
Giải chi tiết:
Ta có: \({V_{A'.ABC}} = \dfrac{1}{2}{V_{A'.ABCD}}\) (do \({S_{\Delta ABC}} = \dfrac{1}{2}{S_{ABCD}}\)) \(\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \dfrac{1}{2}.\dfrac{1}{3}{V_{ABCD.A'B'C'D'}} = \dfrac{1}{6}{V_{ABCD.A'B'C'D'}}\)
\( \Rightarrow {V_{ABCD.A'B'C'D'}} = 6{V_{A'.ABC}} = 6.12 = 72\).
Chọn: D