$S_{toanphan}=2.(AB.AA'+AB.AD+AA'.AD)$
$S_{toanphan}=2.(12.25+12.16+25.16)$
$S_{toanphan}=2.(300+192+400)$
$S_{toanphan}=2.892=1784cm^2$
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$V_{ABCDA'B'C'D'}=AB.AA'.AD$
$V_{ABCDA'B'C'D'}=12.25.16=4800cm^3$
Vậy $S_{toanphan}=1784cm^2, V_{ABCDA'B'C'D'}=4800cm^3$