Đáp án đúng: B
Giải chi tiết:nCH3OOH = 3: 60 =0,05 (mol)
nC2H5OH = 2,76 : 46 = 0,06 (mol)
nCH3COOC2H5 = 2,2:88 = 0,025 (mol)
PTHH:
\(\begin{gathered} C{H_3}COOH + {C_2}{H_5}OH\underset{{}}{\overset{{{H_2}S{O_{4\,}}dac,{t^0}}}{\longleftrightarrow}}\,C{H_3}COO{C_2}{H_5} + {H_2}O \hfill \\ 0,025\,\,\,\,\,\,\,\,\,\,\,\,\, \leftarrow 0,025\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \leftarrow 0,025\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(mol) \hfill \\ \% H = \frac{{{n_{C{H_3}COOH}}pu}}{{{n_{C{H_3}COOH}}bd}}.100\% = \frac{{0,025}}{{0,05}}.100\% = 50\% \hfill \\ \end{gathered} \)
Đáp án B