Đáp án:
$\text{%m$_{C2H5OH}$= 66,2 % }$
$\text{%m$_{C6H5OH}$=33,8%}$
Giải thích các bước giải:
$\text{n$_{H2}$= $\dfrac{3,36}{22,4}$ =0,15 (mol) }$
$\text{C$_{2}$H$_{5}$0H + Na $\longrightarrow$ C$_{2}$H$_{5}$0Na + 1/2H$_{2}$}$
0,24 $\text{$\longleftarrow$}$ 0,15 -0,03 =0,12
$\text{C$_{6}$H$_{5}$0H + Na $\longrightarrow$ C$_{6}$H$_{5}$0Na + 1/2H$_{2}$}$
0,06 $\text{$\longrightarrow$}$ 0,03
$\text{C$_{6}$H$_{5}$0H + 3Br$_{2}$ $\longrightarrow$ C$_{6}$H$_{2}$Br$_{3}$0H + 3HBr}$
0,06 (mol) $\text{$\longleftarrow$}$ 0,06
$\text{n$_{ket tua}$= $\dfrac{19,86}{331}$ }=0,06 (mol)$
$\text{mhh = 0,24.46 + 0,06.94= 16,68 g}$
$\text{%m$_{C2H5OH}$= $\dfrac{0,24.46}{9,78}$.100 = 66,2 % }$
$\text{%m$_{C6H5OH}$= 100- 66,2=33,8 %}$