Không chắc nữa -.-
\[\left \{ {{ax-y=1} \atop {\dfrac{x}{2}-\dfrac{y}{3}=334}} \right.\]
\[⇔\left \{ {{y=ax-1} \atop {\dfrac{x}{2}-\dfrac{ax-1}{3}=334}} \right.\]
\[⇔\left \{ {{y=ax-1} \atop {\dfrac{3x-2(ax-1)}{6}=334}} \right.\]
\[⇔\left \{ {{y=ax-1} \atop {3x-2ax+2=\dfrac{167}{3}}} \right.\]
\[⇔\left \{ {{y=ax-1} \atop {(3-2a)x=\dfrac{161}{3}}} \right.\]
\[⇔\left \{ {{y=ax-1} \atop {x=\dfrac{\dfrac{161}{3}}{3-2a}}} \right.\]
\[\text{Để hệ phương trình vô nghiệm}\] \[⇔3-2a=0⇔a=\dfrac{3}{2}\]
