Đáp án:
\( \to {m_{Zn}} = 16,25{\text{ gam; }}{{\text{m}}_{{H_2}S{O_4}}} = 24,5{\text{ gam; }}{{\text{m}}_{ZnS{O_4}}} = 40,25{\text{ gam}}\)
Giải thích các bước giải:
Phản ứng xảy ra:
\(Zn + {H_2}S{O_4}\xrightarrow{{}}ZnS{O_4} + {H_2}\)
Ta có: \({n_{Zn}} = {n_{{H_2}S{O_4}}} = {n_{ZnS{O_4}}} = {n_{{H_2}}} = \frac{{5,6}}{{22,4}} = 0,25{\text{ mol}}\)
\(\to {m_{Zn}} = 0,25.65 = 16,25{\text{ gam; }}{{\text{m}}_{{H_2}S{O_4}}} = 0,25.98 = 24,5{\text{ gam; }}{{\text{m}}_{ZnS{O_4}}} = 0,25.(65 + 96) = 40,25{\text{ gam}}\)