a) Na2CO3 + Ca(OH)2 => 2NaOH + CaCO3
nCa(OH)2=0,12.1,5=0,18 (mol)
Dựa vào pt, ta thấy:
nNa2CO3=nCa(OH)2=0,18 (mol)
=> mNa2CO3=0,18.106=19,08 (g)
=> mddNa2CO3=(mct.100)/C%=(19,08.100)/10,6=180 (g)
b) nCaCO3=nCa(OH)2=0,18 (mol)
=> mCaCO3=0,18.100=18 (g)