Đáp án:
Giải thích các bước giải:
$2CH3COOH+NaCO3-->2CH3COONa+H2O+CO2$
$nCaCO3=3,36/22,4=0,15(mol)$
$nCH3COOH=2nCO2=0,3(mol)$
=>$mCH3COOH=0,3.60=18(g)$
$CH3COOH+Na--->CH3COONa+H2$(1)
$2C2H5OH+2Na-->2C2H5ONa+H2$(2)
$nH2=8,96/22,4=0,4(mol)$
Theo PTHH1
$nH2=nCH3COOH=0,15(mol)$
=>$nH2(2)=0,4-0,15=0,25(mol)$
Theo PTHH2
$nC2H5OH=2nH2=0,5(mol)$
=>$mC2H5OH=0,5.46=23(g)$
=>$m=mC2H5OH+mCH3COOH=23+18=41(g)$