Cho biểu thức: \(P = \left( {2 - \frac{{2\sqrt x + 1}}{{\sqrt x + 1}}} \right):\left( {\frac{{\sqrt x + 1}}{{\sqrt x + 2}} - \frac{{\sqrt x + 2}}{{\sqrt x - 2}} + \frac{{6\sqrt x + 8}}{{x - 4}}} \right);(0 \le x \ne 4).\)
1) Rút gọn P.
2) Tìm x để: \(P < \frac{1}{2}.\)
A.\(\begin{array}{l}a)\,\,P = \frac{{\sqrt x + 2}}{{\sqrt x + 1}}\\b)\,\,0\,\, < \,\,x\,\, < \,\,25\end{array}\)
B.\(\begin{array}{l}a)\,\,P = \frac{{\sqrt x + 2}}{{\sqrt x + 1}}\\b)\,\,0\,\, \le \,\,x\,\, \le \,\,25\end{array}\)
C.\(\begin{array}{l}a)\,\,P = \frac{{\sqrt x - 2}}{{\sqrt x + 1}}\\b)\,\,0\,\, < \,\,x\,\, < \,\,25\end{array}\)
D.\(\begin{array}{l}a)\,\,P = \frac{{\sqrt x - 2}}{{\sqrt x + 1}}\\b)\,\,0\,\, \le \,\,x\,\, < \,\,25\end{array}\)
