Phân tích : $4\sqrt{2x^2+5x-3}-8$
$= 4.(\sqrt{2x^2+5x-3} - 2)$
$= 4.(\dfrac{(2x^2+5x-7).(\sqrt{2x^2+5x-3}-2}{2x^2+5x-7})$
$= 4.(\dfrac{(2x^2+5x-7).(\sqrt{2x^2+5x-3}-2)}{2x^2+5x-3-4})$
$=4.\dfrac{2x^2+5x-7}{\sqrt{2x^2+5x-3}+2}$
$= 4.\dfrac{(x-1)(2x+7)}{\sqrt{2x^2+5x-3}+2}$