$RCOOH+Na\to RCOONa+0,5H_2$
$n_{H_2}=\dfrac{1,12}{22,4}=0,05(mol)$
Ta có:
$n_{C_2H_3COOH}+n_{C_2H_5COOH}=2n_{H_2}=0,05.2=0,1(mol)$
Hidro hoá hoàn toàn hh thu được axit propionic.
Bảo toàn cacbon, $n_{C_2H_5COOH}=0,1(mol)$
$\to m_{\text{axit}}=0,1.74=7,4g$