Đáp án đúng: A
50% và 50%.
$\begin{array}{l}CuO+2HCl\xrightarrow{{}}CuC{{l}_{2}}+{{H}_{2}}O\\\,\,x\,mol\,\,\,\,\,\,\,\,\,\,\,\,\leftarrow \,\,\,\,\,\,\,\,\,x\,mol\\F{{e}_{2}}{{O}_{3}}+6HCl\xrightarrow{{}}2FeC{{l}_{3}}+3{{H}_{2}}O\\\frac{x}{2}\,mol\,\,\,\,\,\,\,\,\,\,\,\leftarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x\,mol\\\Rightarrow \frac{{{m}_{CuO}}}{{{m}_{F{{e}_{2}}{{O}_{3}}}}}=\frac{80x}{160\frac{x}{2}}=\frac{1}{1}\end{array}$