Đáp án đúng: D
V2 = 3V1.
$\begin{array}{l}\text{Al}\,\text{+}\,\text{NaOH}\,\text{+}\,\text{3}{{\text{H}}_{\text{2}}}\text{O}\xrightarrow{{}}\,\text{NaAl(OH}{{\text{)}}_{\text{4}}}\,\text{+}\,\frac{\text{3}}{\text{2}}{{\text{H}}_{\text{2}}}\\\,\,\,\,\,\,\,\,\,\,\,\,\,{{\text{V}}_{\text{1}}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\xrightarrow{{}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{\text{3}}{\text{2}}{{\text{V}}_{\text{1}}}\\\text{Al}\,\text{+}\,\text{3HCl}\,\xrightarrow{{}}\,\text{AlC}{{\text{l}}_{\text{3}}}\,\text{+}\,\frac{\text{3}}{\text{2}}{{\text{H}}_{\text{2}}}\\\,\,\,\,\,\,\,\,\,\,\,{{\text{V}}_{\text{2}}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\xrightarrow{{}}\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{\text{1}}{\text{2}}{{\text{V}}_{\text{2}}}\\\Rightarrow \,\frac{\text{3}}{\text{2}}{{\text{V}}_{\text{1}}}\,\text{=}\,\frac{\text{1}}{\text{2}}{{\text{V}}_{\text{2}}}\,\Rightarrow \,\frac{{{\text{V}}_{\text{1}}}}{{{\text{V}}_{\text{2}}}}\,\text{=}\,\frac{\text{1}}{\text{3}}\end{array}$
