\(\left[ \begin{array}{l} x = 4\\ x = 1 \end{array} \right.\)
Giải thích các bước giải:
\(\begin{array}{l} P = \dfrac{{x + 2}}{{\sqrt x }} = \sqrt x + \dfrac{2}{{\sqrt x }}\\ P \in Z \to \dfrac{2}{{\sqrt x }} \in Z\\ \to \sqrt x \in U\left( 2 \right)\\ \to \left[ \begin{array}{l} \sqrt x = 2\\ \sqrt x = 1 \end{array} \right.\\ \to \left[ \begin{array}{l} x = 4\\ x = 1 \end{array} \right. \end{array}\)
