$\text{Gọi ƯCLN(2n + 3; n + 2) = d}$
$⇒ \left \{ {{2n+3 \vdots d} \atop {n+2 \vdots d}} \right.$
$⇒ \left \{ {{2n+3 \vdots d} \atop {2(n+2) \vdots d}} \right.$
$⇒ \left \{ {{2n+3 \vdots d} \atop {2n+4 \vdots d}} \right.$
`⇒ (2n+4)-(2n+3) vdots d`
`⇒ 1 vdots d`
$\text{Vậy phân số}$ `A = (2n+3)/(n+2)` $\text{tối giản}$