Đáp án:
\(\begin{array}{l} a,\ V_{O_2}=0,672\ (l).\\ V_{KK}=3,36\ (l).\\ b,\ m_{Al_2O_3}=2,04\ (g).\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l} a,\\ PTHH:4Al+3O_2\xrightarrow{t^o} 2Al_2O_3\\ n_{Al}=\dfrac{2,4.10^{22}}{6.10^{23}}=0,04\ (mol).\\ Theo\ pt:\ n_{O_2}=\dfrac{3}{4}n_{Al}=0,03\ (mol).\\ \Rightarrow V_{O_2}=0,03\times 22,4=0,672\ (l).\\ \Rightarrow V_{KK}=5V_{O_2}=5\times 0,672=3,36\ (l).\\ b,\\ Theo\ pt:\ n_{Al_2O_3}=\dfrac{1}{2}n_{Al}=0,02\ (mol).\\ \Rightarrow m_{Al_2O_3}=0,02\times 102=2,04\ (g).\end{array}\)
chúc bạn học tốt!