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duchieu.training
2 năm trước
cho pt: x^2 - 2(m + 2)x + m^2 - 1 = 0 (với m là tham số) có hai nghiệm x1, x2 lập pt bậc hai có các nghiệm là y1 = 4x1^2 - 1 ; y2 = 4x2^2 - 1 giải chi tiết hộ em với ạ. thanks
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