2Al+3H2SO4---->Al2(SO4)3+3H2
nH2=0,35(mol)
a)mAl=(0,35*2/3)*27=6,3(g);
b)mAl2(SO4)3=(0,35/3)*(27*2+32*3+16*12)=39,9(g);
9
Fe2O3+3H2---->2Fe+3H2O
nFe= 0,75(mol);
a)mFe2O3=(0,75/2)*(56*2+16*3)=60(g);
b)nH2=0,75*3/2=1,125(mol);
vH2=1,125*22,4=25,2(l);
*cho mk 5 sao vs ctlhn nha ban ^-^