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Giangthutrang2001
2 năm trước
Cho tam giác ABC có AB = AC, $\widehat{B}$ = $\widehat{C}$. Kẻ BD vuông góc với AB. Hai đoạn thẳng BD và CE cắt nhau tại I a, Chứng minh : ΔBDC = ΔCEB b, So sánh : $\widehat{IBE}$ và $\widehat{ICD}$ c, Đường thẳng AI cắt BC tại trung điểm H. Chứng minh rằng AI vuông góc với BC
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