\[\begin{array}{l}
\Delta ABC\,\,co:\,\,\,\angle A + \angle B + \angle C = {180^0}\\
\Rightarrow \angle A = {180^0} - {30^0} - {45^0} = {105^0}\\
Ap\,\,dung\,\,dinh\,\,ly\,\,ham\,\,\,so\,\,\,\sin \,\,ta\,\,co:\\
\frac{{BC}}{{\sin \angle A}} = \frac{{AC}}{{\sin \angle B}} = \frac{{AB}}{{\sin \angle C}}\\
\Leftrightarrow \frac{{15 + 15\sqrt 3 }}{{\sin {{105}^0}}} = \frac{{AC}}{{\sin {{30}^0}}} = \frac{{AB}}{{\sin {{45}^0}}}\\
\Rightarrow \left\{ \begin{array}{l}
AC = 15\sqrt 2 \\
AB = 30
\end{array} \right..
\end{array}\]