Ta có: $AB=\sqrt{[6-(-2)]^2+[(-3)-1]^2}=4\sqrt{5}\\AC=\sqrt{[8-(-2)]^2+(4-1)^2}=\sqrt{109}\\BC=\sqrt{(8-6)^2+[4-(-3)]^2}=\sqrt{53}\\\to \text{Chu vi: }4\sqrt{5}+\sqrt{109}+\sqrt{53}$
$S_{ABC}=\dfrac{1}{2}\Bigg|(x_B-x_A)(y_C-y_A)-(x_C-x_A)(y_B-y_A)\Bigg|\\\to S_{ABC}=\dfrac{1}{2}\Bigg|[6-(-2)](4-1)-[8-(-2)](-3-1)\Bigg|\\\hspace{1,7cm}=32$