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ph0810
2 năm trước
cho tam giác ABC vuông tại A (AB>AC). gọi M là trung điểm của BC .trên tia đối của tia MA lấy điểm D sao cho MD=MA a, Cho AB = 8cm, BC = 10cm . Tính AC b, CM : ∆AMB = ∆DMC ,từ đó suy ra CD ⊥ AC c, Vẽ AH ⊥ với BC tại H , trên tia đối của HA lấy E sao cho HE = HA . CM : ∆ACE cân d, CM : BD = CE ( Vẽ hình giúp mình luôn nhé . Mình cảm ơn)
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