Ta có:
$∆ABC$ vuông tại $A$
$\Rightarrow \widehat{B} + \widehat{C}= 90^o$
$\Rightarrow \widehat{B}=90^o - \widehat{C}=90^o - 25^o = 65^o$
Ta được:
$\sin C = \dfrac{AB}{BC}$
$\Rightarrow AB = BC.\sin C = 10.\sin25^o \approx 4,2262 \,cm$
$\cos C = \dfrac{AC}{BC}$
$\Rightarrow AC = BC.\cos C = 10.\cos25^o \approx 9,0631\, cm$