Đáp án:
\({S_{EHK}} \approx 43,78\,\,\,\left( {dvdt} \right)\)
Giải thích các bước giải:
\(\begin{array}{l}
\angle K = {180^0} - \left( {\angle E + \angle H} \right) = {180^0} - \left( {{{30}^0} + {{40}^0}} \right) = {110^0}.\\
Ap\,\,dung\,\,dinh\,\,ly\,\,\,ham\,\,\,so\,\,\,\sin \,\,\,ta\,\,\,co:\\
\frac{{EH}}{{\sin \angle K}} = \frac{{KH}}{{\sin \angle E}} \Rightarrow KH = \frac{{EH.\sin \angle E}}{{\sin \angle K}} = \frac{{16.\sin {{30}^0}}}{{\sin {{110}^0}}} \approx 8,513\,\,\left( {dvdd} \right).\\
\Rightarrow {S_{EHK}} = \frac{1}{2}KH.EH.\sin \angle H\\
= \frac{1}{2}.8,513.16.sin{40^0} \approx 43,78\,\,\,\left( {dvdt} \right).
\end{array}\)
