Cho tích phân \(I = \int\limits_0^{{\pi \over 4}} {\left( {x - 1} \right)\sin 2xdx} \). Tìm đẳng thức đúng?
A.\(I = - \left( {x - 1} \right)\cos 2x|_0^{{\pi \over 4}} + \int\limits_0^{{\pi \over 4}} {\cos 2xdx} \)
B.\(I = - \left( {x - 1} \right)\cos 2x|_0^{{\pi \over 4}} - \int\limits_0^{{\pi \over 4}} {\cos 2xdx} \)
C.\(I = - {1 \over 2}\left( {x - 1} \right)\cos 2x|_0^{{\pi \over 4}} + {1 \over 2}\int\limits_0^{{\pi \over 4}} {\cos 2xdx} \)
D.\(I = - {1 \over 2}\left( {x - 1} \right)\cos 2x|_0^{{\pi \over 4}} - {1 \over 2}\int\limits_0^{{\pi \over 4}} {\cos 2xdx} \)
A.\(I = - \left( {x - 1} \right)\cos 2x|_0^{{\pi \over 4}} + \int\limits_0^{{\pi \over 4}} {\cos 2xdx} \)
B.\(I = - \left( {x - 1} \right)\cos 2x|_0^{{\pi \over 4}} - \int\limits_0^{{\pi \over 4}} {\cos 2xdx} \)
C.\(I = - {1 \over 2}\left( {x - 1} \right)\cos 2x|_0^{{\pi \over 4}} + {1 \over 2}\int\limits_0^{{\pi \over 4}} {\cos 2xdx} \)
D.\(I = - {1 \over 2}\left( {x - 1} \right)\cos 2x|_0^{{\pi \over 4}} - {1 \over 2}\int\limits_0^{{\pi \over 4}} {\cos 2xdx} \)
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Hóa Học lớp 12
