Giải thích các bước giải:
a.Ta có :
$x:y:z=5:3:4$
$\to \dfrac x5=\dfrac y3=\dfrac z4=\dfrac{2y}{6}=\dfrac{x+2y-z}{5+6-4}=\dfrac{-121}{7}$
$\to x=-\dfrac{605}{7}, y=\dfrac{-363}{7}, z=\dfrac{-484}{7}$
b.Ta có :
$\dfrac x3=\dfrac y7=\dfrac z5=k$
$\to x=3k, y=7k, z=5k$
$\to x^2-y^2+z^2=(3k)^2-(7k)^2+(5k)^2=-15k^2=-60\to k^2=4\to k=\pm2$
$+)k=2\to x=6,y=14,z=10$
$+)k=-2\to x=-6,y=-14,z=-10$