Đáp án:
Giải thích các bước giải:
`a)(a-b)^3`
`=a^3-3a^2b+3ab^2-b^3`
`=-(b^3-3b^2a+3a^2b-a^3)`
`=-(b-a)^3`
`b)(-a-b)^2`
`=(-a)^2-2(-a).b+(-b)^2`
`=a^2+2ab+b^2`
`=(a+b)^2`
a) -(b-a) ³
= -( b-a) . [-(b-a)] .[-(b-a)]
= (a-b).(a-b).(a-b)
= (a-b) ³
Ta có : -(A -B) = B - A
b) (-a-b) ²
= -(a + b)²
= -(a +b).[-(a+b)]
= (a +b).(a+b)
= (a+b) ²
Ta có : -a .(-b) = a.b
Nocopy
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