Đáp án:
Ta có: (2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)
=1.(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)
=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)
=(2²-1²)(2^2+1)(2^4+1)(2^8+1)(2^16+1)
=(2^4-1^4)(2^4+1)(2^8+1)(2^16+1)
=(2^8-1^8)(2^8+1)(2^16+1)
=(2^16-1^16)(2^16+1)
=2^32-1^32
=2^32-1(ĐPCM)
XIN TLHN VÀ 5* NHÉ