Giải thích các bước giải:
`1/1^2+1/2^2+1/3^2+...+1/100^2`
Có `1/1^2>1/1.2`
`1/2^2>1/2.3`
`1/3^2>1/3.4`
`...................`
`1/100^2>1/100.101`
`=> 1/1^2+1/2^2+1/3^2+...+1/100^2>1/1.2+1/2.3+1/3.4+...+1/100.101`
`=1-1/2+1/2-1/3+1/3-1/4+...+1/100-1/101=1-1/101=100/101`
Vậy `1/1^2+1/2^2+1/3^2+...+1/100^2 >100/101.`