Bạn tham khảo :
Đặt $A = 5 + 5^2+5^3+5^4+ ... +5^{29} + 5^{30}$
$5 + 5^2+5^3+5^4+ ... +5^{29} + 5^{30}$
$= (5+5^2) + (5^3+ 5^4) +.. + (5^{29} + 5^{30}$
$= 5 ( 1 + 5) + 5^3 ( 1+5) + ... + 5^{29} (1+5)$
$= 5.6 + 5^3.6 + ... + 5^{29} . 6$
$= 6 ( 5 + 5^3 + 5^{29}) \vdots 6$