Em tham khảo nha:
\(\begin{array}{l}
1)\\
a)\,S{O_3} + {H_2}O \to {H_2}S{O_4}\\
b)\,{P_2}{O_5} + 3{H_2}O \to 2{H_3}P{O_4}\\
c)\,Ba{(OH)_2} + S{O_3} \to BaS{O_4} + {H_2}O\\
d)\,2KOH + S{O_2} \to {K_2}S{O_3} + {H_2}O\\
e)\,Ca{(OH)_2} + C{O_2} \to CaC{O_3} + {H_2}O\\
f)\,2NaOH + C{O_2} \to N{a_2}C{O_3} + {H_2}O\\
g)\,S{O_2} + 2KOH \to {K_2}S{O_3} + {H_2}O\\
h)\,Ca{(OH)_2} + S{O_2} \to CaS{O_3} + {H_2}O\\
i)BaO + C{O_2} \to BaC{O_3}\\
j)\,{K_2}O + S{O_3} \to {K_2}S{O_4}\\
2)\\
a)\,\\
(1)\,S{O_3} + {H_2}O \to {H_2}S{O_4}\\
(2)\,{K_2}O + {H_2}S{O_4} \to {K_2}S{O_4} + {H_2}O\\
b)\\
(1)4P + 5{O_2} \xrightarrow{t^0} 2{P_2}{O_5}\\
(2){P_2}{O_5} + 3{H_2}O \to 2{H_3}P{O_4}\\
(3)\,{H_3}P{O_4} + 3NaOH \to N{a_3}P{O_4} + 3{H_2}O\\
3)\\
a)\\
S{O_2} + 2NaOH \to N{a_2}S{O_3} + {H_2}O\\
N{a_2}S{O_3}:\,Natri\,sunfit\\
{n_{S{O_2}}} = \dfrac{{2,479 \times 0,99}}{{0,082 \times (273 + 25)}} = 0,1\,mol\\
{n_{N{a_2}S{O_3}}} = {n_{S{O_2}}} = 0,1\,mol\\
{m_{N{a_2}S{O_3}}} = 0,1 \times 126 = 12,6g\\
b)\\
{n_{NaOH}} = 2{n_{S{O_2}}} = 0,2\,mol\\
{C_M}NaOH = \dfrac{{0,2}}{{0,5}} = 0,4M
\end{array}\)
