`(4x^2-25)^2-9(2x-5)^2=0`
`<=>` $\left[\begin{array}{ccc}(2x-5)(2x+5)\\\end{array}\right]^2-9(2x-5)^2=0$
`<=>` $(2x-5)^{2}(2x+5)^2-9(2x-5)^2=0$
`<=>` $(2x-5)^{2}(4x^2+20x+25-9)=0$
`<=>` $(2x-5)^{2}(4x^2+20x+16)=0$
`<=>` $(2x-5)^{2}(4x^2+4x+16x+16)=0$
`<=>` $(2x-5)^{2}(x+1)(4x+16)=0$
`=>` \(\left[ \begin{array}{l}(2x-5)^2=0\\x+1=0\\4x+16=0\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}2x-5=0\\x+1=0\\4x+16=0\end{array} \right.\)
`=>` \(\left[ \begin{array}{l}x=\dfrac{5}{2}\\x=-1\\x=-4\end{array} \right.\)
$\text{Vậy phương trình có nghiệm : }$ \(\left[ \begin{array}{l}x=\dfrac{5}{2}\\x=-1\\x=-4\end{array} \right.\)
`@K`
