Em tham khảo nha :
\(\begin{array}{l}
a)\\
{M_{hh}} = 16,22 \times 2 = 32,44dvC\\
{n_{hh}} = \dfrac{{20,16}}{{22,4}} = 0,9mol\\
hh:{H_2}S(a\,mol),{O_2}(b\,mol)\\
\dfrac{{34a + 32 \times (0,9 - a)}}{{0,9}} = 32,44\\
\Rightarrow a = 0,2mol\\
\% {V_{{H_2}S}} = \dfrac{{0,2 \times 22,4}}{{20,16}} \times 100\% = 22,2\% \\
\% {V_{{O_2}}} = 100 - 22,2 = 77,8\% \\
b)\\
2{H_2}S + 3{O_2} \to 2S{O_2} + 2{H_2}O\\
\dfrac{{0,2}}{1} < \dfrac{{0,7}}{3} \Rightarrow {O_2}\text{ dư}\\
{n_{S{O_2}}} = {n_{{H_2}O}} = 0,2mol\\
S{O_2} + {H_2}O \to {H_2}S{O_3}\\
{n_{{H_2}S{O_3}}} = {n_{S{O_2}}} = 0,2mol\\
{C_M} = \dfrac{{0,2}}{{0,0946}} = 2,11M\\
C\% = \dfrac{{0,2 \times 82}}{{94,6 + 0,2 \times 64}} \times 100\% = 15,27\%
\end{array}\)