Đáp án + giải thích các bước giải:
`150ml=0,15l;250ml=0,25l`
`m_{\text{dd HCL 10%}}=D.V=1,047.150=157,05(g)`
`C%=(m_{ct}.100%)/(m_{dd})->10%=(n_{\text{dd HCL 10%}}.M_{HCL}.100%)/(157,05)->n_{\text{dd HCL 10%}}=(10%)/((36,5.100%)/(157,05))=3141/7300(mol)`
`n_{\text{dd HCL 2M}}=C_M.V=2.0,25=1/2(mol)`
`C_{M_A}=n/V=(3141/7300+1/2)/(0,15+0,25)=6791/2920(M)`