Đáp án:
\(11\Omega \)
Giải thích các bước giải:
Ta có:
\[R = \rho \frac{l}{S} \Rightarrow \frac{{{R_2}}}{{{R_1}}} = \frac{{{\rho _2}}}{{{\rho _1}}}.\frac{{{l_2}}}{{{l_1}}}.\frac{{{S_1}}}{{{S_2}}} = \frac{{2,{{8.10}^{ - 8}}}}{{1,{{7.10}^{ - 8}}}}.\frac{{{l_2}}}{{0,75{l_2}}}.\frac{{0,5{S_2}}}{{{S_2}}} = 1,1 \Rightarrow {R_2} = 1,1.10 = 11\Omega \]