Ta có:
`2``+``\frac{5}{x+1}``=``\frac{3x+4}{x+1}`
`<=>` `\frac{2x+2}{x+1}``+``\frac{5}{x+1}``=``\frac{3x+4}{x+1}`
`<=>` `2x``+``1``+``5``-3x``+``4``=` `0`
`Đ``K``X``Đ`: `x``+``1``\ne``0``->` `x``\ne``-1`
`<=>` `-``x``+``3``=``0`
`<=>` `x``=``3`( nhận)
Vậy `x``=``3` thì `2``+``\frac{5}{x+1}``=``\frac{3x+4}{x+1}`