`a)`
`n = {6,72+ 16,8 + 17,92 + 3,36}/{22,4} = 2(mol)`
`b)`
`m = {6,72}/{22,4} .2 + {16,8}/{22,4} . 32 + {17,92}/{22,4}. 28 + {3,36}/{22,4} .44= 53,6(g)`
`c)`
`V = 6,72+ 16,8- 17,92 + 3,36= 44,8(l)`
`%V_{H_2} = {6,72}/{44,8} .100= 15%`
`%V_{O_2}={16,8}/{44,8} .100= 37,5%`
`%V_{N_2} = {17,92}/{44,8} .100= 40%`
`%V_{CO_2} = 100-15-37,5+40= 7,5%`